Ian, the old 18" was from the days of plastic tanks! The wet wing is around 23 or 24 ". Measure from leading edge to middle of tank to be sure.
Your empty C of G would be Tail weight 62lbs x around 196" (measure from door post to tail wheel axle to get real #) divided by the total weight of 737lb = 16.49" aft of datum.
I am assuming that you put the rear floor in and this is what makes your tail weigh 62 pounds in level flight attitude, thus causing the fairly aft empty C of G thanks to the light engine up front with your 912ULS - 100HP. The 912 powered AULA Rebel I built was only
649 lbs total empty weight with 42 on the tail for an empty C of G of 12.68" (it didn't have the rear floor installed).
Don't know what you pegged on yours for gross weight, but my Rebel worked just fine when it originally had the 100 HP Lycoming in it and still climbed well even when loaded up to, uuuchhumm, 1800+lbs. I know MAM recommended 1450 for the 912 powered Rebels, but you should be able to go the full 1650 on the 100HP x 912S. The problem with the empty C of G being at around 16.5" is that you may go out the rear "limit" before you can get the weight into her.
If you have both 22 gallon US tanks that's 264lbs of fuel. Two 200lb guys and 737 empty would bring you to 1401. Leaves 249 for survival gear ( or 8 cases of Fosters!) Lets see if you can fly that!
737 (empty)x 16.49" =12153.13
400 (2 people)x 15" = 6000.00
249 (baggage)x 43" = 10707.00
264 (fuel) x 23" = 6072.00
1650 34932.13
34932.13/1650 gives a C of G of 21.17 inches so just out the back end of the (old 19.7) recommended limit by 1.47"
If you lower your "case count" to 5 and only had about 150lbs of baggage, the c of g would work out to:
737 x 16.49 = 12153.13
400 x 15 = 6000.00
264 x 23 = 6072.00
150 x 43 = 6450.00
1551 30675.13
That gives 19.77 inches aft of datum and .07 out the aft limit. Move the baggage an inch closer to the seats and your fine!
Cheers,
Wayne G. O'Shea
www.irishfield.on.ca
----- Original Message -----
From: Ian Donaldson (
allsure@iprimus.com.au)
To: murphy-rebel@dcsol.com (
murphy-rebel@dcsol.com)
Sent: Monday, June 10, 2002 3:48 AM
Subject: Re Rebel Centre of Gravity
G'day
I'm just a little confused with the method of C of G calculations that are detailed in the construction manual, and I would appreciate some assistance.
My Rebel weights are as follows;
Left wheel 348 lb
Right wheel 327 lb
Tailwheel
62 lb
Total
737 lb
Now just what distances should I use to determine the C of G?
One page of the manual says:
Pilot & passenger 15'"
Baggage 43"
Fuel 18"
Whereas over the next page in the manual, the distances are shown as;
Pilot & passenger 15"
Baggage 45"
Fuel 23"
What should I use?
Can anyone do a sample calculation for me please?
Thanks and regards
Ian Donaldson